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This system cannot be time-invariant because the function of the output has a constant k that gets changed everytime one selects a value of k. This changes the amplitude of the output function, making it not correspond to the input function and therefore cannot be time-invariant. | This system cannot be time-invariant because the function of the output has a constant k that gets changed everytime one selects a value of k. This changes the amplitude of the output function, making it not correspond to the input function and therefore cannot be time-invariant. | ||
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| + | ==Problem 6b== | ||
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| + | The table indicates that if the input is <math>\delta[n]</math> then the output is <math>\delta[n-1]</math>. Therefore, if the system is linear, for the output to be <math>u[n-1]</math>, the input then needs to be <math>u[n]</math>. | ||
Latest revision as of 20:57, 11 September 2008
Problem 6a
This system cannot be time-invariant because the function of the output has a constant k that gets changed everytime one selects a value of k. This changes the amplitude of the output function, making it not correspond to the input function and therefore cannot be time-invariant.
Problem 6b
The table indicates that if the input is $ \delta[n] $ then the output is $ \delta[n-1] $. Therefore, if the system is linear, for the output to be $ u[n-1] $, the input then needs to be $ u[n] $.
