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== Time Invariance check ==
 
== Time Invariance check ==
  Let us check for y[n] = x[n]^2
+
  Let us check for '''y[n] = x[n]^2'''
  
 
*<math>y[x[n-n0]] = x{[n-n0]^2}</math>  
 
*<math>y[x[n-n0]] = x{[n-n0]^2}</math>  
 
Also,
 
Also,
 
*<math>y[n-n0] = x{[n-n0]^2}</math>
 
*<math>y[n-n0] = x{[n-n0]^2}</math>
Thus the above system is time invariant
+
Thus the above system is '''time invariant'''
  
  
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Let us test for  
 
Let us test for  
 
  '''y[n]=cos[nQ]*x[n]'''
 
  '''y[n]=cos[nQ]*x[n]'''
 +
 +
*y[x[n-n0]]=cos[nQ]*x[n-n0]
 +
Also,
 +
*y[n-n0]= cos[n-n0]* x[n-n0]
 +
 +
Thus from above we can say that the system is '''time variant'''

Revision as of 11:09, 12 September 2008

Time invariance

A system is called time invariant if the cascade

x[n]----->Time delay ----> System -----> z[n] yields the same output as x[n]----->system----->Time Delay-----> y[n]


Time Invariance check

Let us check for y[n] = x[n]^2
  • $ y[x[n-n0]] = x{[n-n0]^2} $

Also,

  • $ y[n-n0] = x{[n-n0]^2} $

Thus the above system is time invariant


Time Variance check

Let us test for

y[n]=cos[nQ]*x[n]
  • y[x[n-n0]]=cos[nQ]*x[n-n0]

Also,

  • y[n-n0]= cos[n-n0]* x[n-n0]

Thus from above we can say that the system is time variant

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett