(Example of a Time Variant System)
 
Line 50: Line 50:
 
After applying the function to the system <math>\,s(t)\,</math>, we get:
 
After applying the function to the system <math>\,s(t)\,</math>, we get:
  
<math>\,y(t)=2x(t-3)\,</math>
+
<math>\,y(t)=2x(3t-3)\,</math>
  
 
Thus,
 
Thus,
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<math>\,y(t-t_o)=\,</math>
 
<math>\,y(t-t_o)=\,</math>
  
<math>\,2x((t-t_o)-3)=\,</math>
+
<math>\,2x(3(t-t_o)-3)=\,</math>
  
<math>\,2x(t-t_o-3)\,</math>
+
<math>\,2x(3t-3t_o-3)\,</math>
  
  
 
Now, apply <math>\,x(t-t_o)\,</math> to the system <math>\,s(t)\,</math>:
 
Now, apply <math>\,x(t-t_o)\,</math> to the system <math>\,s(t)\,</math>:
  
<math>\,2x((t-3)-t_o)\,</math>
+
<math>\,2x((3t-3)-t_o)\,</math>
  
<math>\,2x(t-3-t_o)\,</math>
+
<math>\,2x(3t-3-t_o)\,</math>
  
  
Since these two are equal
+
Since these two are not equal
  
<math>\,2x(t-t_o-3)=2x(t-3-t_o)\,</math>
+
<math>\,2x(3t-3t_o-3)\not= 2x(3t-3-t_o)\,</math>
  
the system is time invariant.
+
the system is time variant.

Latest revision as of 20:05, 11 September 2008

Definition of Time Invariance

A system $ \,s(t)\, $ is called time invariant if for any input signal $ \,x(t)\, $ yielding output signal $ \,y(t)\, $ and for any $ \,t_o\in\mathbb{R}\, $, the response to $ \,x(t-t_o)\, $ is $ \,y(t-t_o)\, $.

Example of a Time Invariant System

The following system is time invariant:

$ \,s(t)=2x(t-3)\, $


Proof:

We have a function $ \,x(t)\, $.

After applying the function to the system $ \,s(t)\, $, we get:

$ \,y(t)=2x(t-3)\, $

Thus,

$ \,y(t-t_o)=\, $

$ \,2x((t-t_o)-3)=\, $

$ \,2x(t-t_o-3)\, $


Now, apply $ \,x(t-t_o)\, $ to the system $ \,s(t)\, $:

$ \,2x((t-3)-t_o)\, $

$ \,2x(t-3-t_o)\, $


Since these two are equal

$ \,2x(t-t_o-3)=2x(t-3-t_o)\, $

the system is time invariant.

Example of a Time Variant System

The following system is time variant:

$ \,s(t)=2x(3t-3)\, $


Proof:

We have a function $ \,x(t)\, $.

After applying the function to the system $ \,s(t)\, $, we get:

$ \,y(t)=2x(3t-3)\, $

Thus,

$ \,y(t-t_o)=\, $

$ \,2x(3(t-t_o)-3)=\, $

$ \,2x(3t-3t_o-3)\, $


Now, apply $ \,x(t-t_o)\, $ to the system $ \,s(t)\, $:

$ \,2x((3t-3)-t_o)\, $

$ \,2x(3t-3-t_o)\, $


Since these two are not equal

$ \,2x(3t-3t_o-3)\not= 2x(3t-3-t_o)\, $

the system is time variant.

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood