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If X1(t) -> system => y1(t) and X2(t) -> system => y2(t)implies a*X1(t)+ b*X2(t) -> system => a*y1(t) + b*y2(t)
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If X1(t) -> system => y1(t) and X2(t) -> system => y2(t) implies a*X1(t)+ b*X2(t) -> system => a*y1(t) + b*y2(t)
  
 
for any complex number a,b
 
for any complex number a,b
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y(t)=<math>x^2 (t)</math> is non-linear
 
y(t)=<math>x^2 (t)</math> is non-linear
  
Since a*y1(t) + b*y2(t)=<math>(a*X1(t)+ b*X2(t))^2= (a*X1(t))^2+ 2*(a*X1(t)*(b*X2(t)) + (b*X2(t))^2
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Since a*y1(t) + b*y2(t)=<math>(a*X1(t)+ b*X2(t))^2= (a*X1(t))^2+ 2*(a*X1(t)*(b*X2(t)) + (b*X2(t))^2 </math>
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Latest revision as of 16:05, 10 September 2008

If X1(t) -> system => y1(t) and X2(t) -> system => y2(t) implies a*X1(t)+ b*X2(t) -> system => a*y1(t) + b*y2(t)

for any complex number a,b

then the system is called linear.


E.g.

y(t)=$ x^2 (t) $ is non-linear


Since a*y1(t) + b*y2(t)=$ (a*X1(t)+ b*X2(t))^2= (a*X1(t))^2+ 2*(a*X1(t)*(b*X2(t)) + (b*X2(t))^2 $


y(t)=2(x)t is linear

Since a*y1(t) + b*y2(t)=2*(a*X1(t)+ b*X2(t))= 2*a*X1(t)+ 2*b*X2(t)

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Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett