(A linear function)
(Prove)
 
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== A linear function ==
 
== A linear function ==
  we have seen is a function whose graph lies on a straight line,  
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we have seen is a function whose graph lies on a straight line,  
 
and which can be described by giving its slope and its y intercept
 
and which can be described by giving its slope and its y intercept
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== Linearity ==
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If both system yield the same output function, this is called a linear system.
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== Prove ==
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y(t)=2x(t)
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[1]
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x1(t)--->[system]---->y1(t)=2x1(t)---->*a---(1) a*2*x1(t)
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x2(t)--->[system]---->y2(t)=2x2(t)---->*b---(2) b*2*x2(t)
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(1)+(2)= 2ax1(t)+2bx2(t)
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[2]
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x1(t)--->*a---(3) a*x1(t)
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x2(t)--->*b---(4) b*x2(t)
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(3)+(4)=a*x1(t)+b*x2(t) ---->[system]---->2(a*x1(t)+b*x2(t))=2ax1(t)+2bx1(t)
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The results of [1] and [2] are the same. Thus, this is linear system.
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y(t)=x(t)^2
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[3]
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x1(t)--->[system]---->y1(t)=x1(t)^2---->*a---(5) a*x1(t)^2
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x2(t)--->[system]---->y2(t)=x2(t)^2---->*b---(6) b*x2(t)^2
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(5)+(6)= a*x1(t)^2+b*x2(t)^2
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[4]
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x1(t)--->*a---(7) a*x1(t)
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x2(t)--->*b---(8) b*x2(t)
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(7)+(8)=a*x1(t)+b*x2(t) ---->[system]---->(a*x1(t)+b*x2(t))^2
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The results of [3] and [4] are not the same. Thus, this is non-linear system.

Latest revision as of 05:03, 12 September 2008

A linear function

we have seen is a function whose graph lies on a straight line, and which can be described by giving its slope and its y intercept

Linearity

If both system yield the same output function, this is called a linear system.


Prove

y(t)=2x(t)

[1]

x1(t)--->[system]---->y1(t)=2x1(t)---->*a---(1) a*2*x1(t)

x2(t)--->[system]---->y2(t)=2x2(t)---->*b---(2) b*2*x2(t)

(1)+(2)= 2ax1(t)+2bx2(t)


[2]

x1(t)--->*a---(3) a*x1(t)

x2(t)--->*b---(4) b*x2(t)

(3)+(4)=a*x1(t)+b*x2(t) ---->[system]---->2(a*x1(t)+b*x2(t))=2ax1(t)+2bx1(t)

The results of [1] and [2] are the same. Thus, this is linear system.


y(t)=x(t)^2

[3]

x1(t)--->[system]---->y1(t)=x1(t)^2---->*a---(5) a*x1(t)^2

x2(t)--->[system]---->y2(t)=x2(t)^2---->*b---(6) b*x2(t)^2

(5)+(6)= a*x1(t)^2+b*x2(t)^2


[4]

x1(t)--->*a---(7) a*x1(t)

x2(t)--->*b---(8) b*x2(t)

(7)+(8)=a*x1(t)+b*x2(t) ---->[system]---->(a*x1(t)+b*x2(t))^2

The results of [3] and [4] are not the same. Thus, this is non-linear system.

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