(New page: <pre> If we have the system x(t) and it gives the output y(t), then the system is linear if you can multiply the input by any scalar value and the output will be multiplied by the scalar ...)
 
 
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x(t) -> y(t) then ax(t) -> ay(t).
 
x(t) -> y(t) then ax(t) -> ay(t).
 
</pre>
 
</pre>
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== Linear ==
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If the system is 2(x(t))
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If x(t)= sin(t)
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x(t) ->[2(x(t))]-> 2(y(t)) or 2*sin(t)
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== Non-Linear ==
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If the system is <math>\int(x(t))</math>
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If x(t)= <math>t^2</math>
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x(t) ->[<math>\int x(t)</math>]-> (y(t)) or <math>t^3 \over 3</math>
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If the input is multiplied by 1/3 it is not the same as multiplying the output by 1/3

Latest revision as of 05:43, 12 September 2008

If we have the system x(t) and it gives the output y(t), then the system is linear if you 
can multiply the input by any scalar value and the output will be multiplied by the scalar as well. 

x(t) -> y(t) then ax(t) -> ay(t).

Linear

If the system is 2(x(t))

If x(t)= sin(t)

x(t) ->[2(x(t))]-> 2(y(t)) or 2*sin(t)

Non-Linear

If the system is $ \int(x(t)) $

If x(t)= $ t^2 $

x(t) ->[$ \int x(t) $]-> (y(t)) or $ t^3 \over 3 $

If the input is multiplied by 1/3 it is not the same as multiplying the output by 1/3

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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett