Revision as of 13:13, 12 September 2008 by Jrathrey (Talk)

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now If X(t)-----> System---->z1(t)$ \times $a---->a.z1(t) 

                                                              $ \downarrow $

      Y(t)-----> System---->z2(t)$ \times $b---->b.z2(t)
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Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett