Revision as of 14:05, 10 September 2008 by Cocker (Talk)

Part A

Can the system be time invariant?

Lets test and find out:

Part B

The system does a phase shift to the right by 1 unit and then multiplies the amplitude of the function by the square of total shift.

if Y[n] = u[n-1]

then in the function $ \delta[n-(k+1)] $ k must be equal to 0

we then multiply the amplitude by the square of the total shift (-1), which has no effect because it is the same as multiplying by 1.

We can finally solve and say that in order to produce Y[n], the input must be $ x(t) = u(t) $

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang