(New page: == Part A, 1. == Using a CT signal that was posted in Homework 1, it is possible to create both a periodic and non-periodic DT signal, depending on what sampling frequency one chooses. Th...) |
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| − | == Part A | + | == Part A: Periodic Signals Revisited == |
| − | + | By sampling a CT periodic signal at different frequencies, one can produce both a periodic and non-periodic DT signal. I chose to use the tangent signal from Homework 1. | |
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:<center><math>\tan\theta = \frac{\sin\theta}{\cos\theta}\,</math></center> | :<center><math>\tan\theta = \frac{\sin\theta}{\cos\theta}\,</math></center> | ||
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<center>[[Image:tangent_ECE301Fall2008mboutin.jpg]]</center> | <center>[[Image:tangent_ECE301Fall2008mboutin.jpg]]</center> | ||
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| + | By sampling the signal with x[n]=tan[k+n] and k=1.5, it is possible to produce a non-periodic DT signal. | ||
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| + | <center>[[Image:tan_nonperiodic_ECE301Fall2008mboutin.jpg]]</center> | ||
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| + | By sampling the signal with x[n]=tan[k+n] and <math>k = {\pi\over 8}</math> | ||
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| + | <center>[[Image:tan_periodic_ECE301Fall2008mboutin.jpg]]</center> | ||
Revision as of 10:40, 11 September 2008
Part A: Periodic Signals Revisited
By sampling a CT periodic signal at different frequencies, one can produce both a periodic and non-periodic DT signal. I chose to use the tangent signal from Homework 1.
$ \tan\theta = \frac{\sin\theta}{\cos\theta}\, $
By sampling the signal with x[n]=tan[k+n] and k=1.5, it is possible to produce a non-periodic DT signal.
By sampling the signal with x[n]=tan[k+n] and $ k = {\pi\over 8} $
