(New page: == Homework 2 Part A-1== I chose the signal: <math>y = cos(n)\,</math>)
 
 
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== Homework 2 Part A-1==
 
== Homework 2 Part A-1==
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<br>
 
I chose the signal:
 
I chose the signal:
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<br>
 
<math>y = cos(n)\,</math>
 
<math>y = cos(n)\,</math>
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<br>
 +
When I took a sample at 1 hz, the signal was ugly and random.
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<br>
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Therefore it is not periodic.
 +
 +
[[Image:Non-periodic.jpg‎_ECE301Fall2008mboutin]]
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<br>Changing the function to:<math>y = cos(n*pi/2)\,</math><br>
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made the signal look periodic.
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<br>
 +
[[Image:Periodiccnphilli_ECE301Fall2008mboutin.JPG]]
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<br>
 +
 +
== Part A-2 ==
 +
<br>
 +
I chose the signal y=log(x)
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<br>
 +
This code is not periodic, but taking a piece of it and<br>
 +
Repeating it will make it periodic<br>
 +
[[Image:LogA-2_ECE301Fall2008mboutin.JPG]]
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<pre>
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Here is the code I used:
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 +
dt = .00001;
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periodlength = 5;
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periods = 10;
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t = [dt:dt:periodlength];
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y = log(t);
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x = [];
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for i=1:periods
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  x = [x,y];
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end
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t = [dt:dt:periodlength*periods];
 +
plot(t,x)
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</pre>

Latest revision as of 14:54, 11 September 2008

Homework 2 Part A-1


I chose the signal:
$ y = cos(n)\, $
When I took a sample at 1 hz, the signal was ugly and random.
Therefore it is not periodic.

File:Non-periodic.jpg ECE301Fall2008mboutin
Changing the function to:$ y = cos(n*pi/2)\, $
made the signal look periodic.
Periodiccnphilli ECE301Fall2008mboutin.JPG

Part A-2


I chose the signal y=log(x)
This code is not periodic, but taking a piece of it and
Repeating it will make it periodic
LogA-2 ECE301Fall2008mboutin.JPG

Here is the code I used:

dt = .00001;
periodlength = 5;
periods = 10;

t = [dt:dt:periodlength];
y = log(t);
x = [];
for i=1:periods
   x = [x,y];
end
t = [dt:dt:periodlength*periods];
plot(t,x)

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