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For the signal to be periodic, there must exist an integer N such that <math>x[n]=x[n+N]</math>.  For the signal defined as it is here, no such integer N exists.
 
For the signal to be periodic, there must exist an integer N such that <math>x[n]=x[n+N]</math>.  For the signal defined as it is here, no such integer N exists.
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'''Changing a Periodic Continuous Time Signal to a Periodic Discrete Time Signal'''
 
'''Changing a Periodic Continuous Time Signal to a Periodic Discrete Time Signal'''
  
Suppose our sampling frequency, instead of being 1, was <math>\frac{\pi}{8}</math>.
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Suppose our sampling frequency, instead of being 1, was <math>\frac{\pi}{8}</math>. Then the newly sampled function overlaid with the continuous function would look something like
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[[Image:hw2a1d_blaskows_ECE301Fall2008mboutin.jpg|frame|center|300px|The periodic discrete-time function <math>x[n]=sin(\frac{\pi}{8}n)</math> overlaid with its continuous time equivalent.]]
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[[Image:hw2a1e_blaskows_ECE301Fall2008mboutin.jpg|frame|center|300px|The periodic discrete-time function <math>x[n]=sin(\frac{\pi}{8}n)</math>.]]
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==Part 2==
 
==Part 2==
 
To be completed...
 
To be completed...

Revision as of 07:06, 10 September 2008

Part 1

Changing a Periodic Continuous Time Signal to a Non-Periodic Discrete Time Signal

One can take a signal that would be periodic in continuous time and turn it into a signal that is not periodic in discrete time. Consider the continuous time signal $ x(t)=sin(t) $. Plotting this signal yields a smooth waveform that repeats itself with period $ T=2\pi $.

The continuous-time signal $ x(t)=sin(t) $ is periodic.

Sampling this signal at every integer time yields something altogether different.

Sampling the continuous-time signal $ x(t)=sin(t) $ at integer times yields something like this. Note that the new discrete-time function $ x[n]=sin(n) $ is not periodic. Here we have shown five cycles of the formerly-periodic continuous time function.

The new discrete time function looks like this on its own.

The non-periodic discrete-time function $ x[n]=sin(n) $.

For the signal to be periodic, there must exist an integer N such that $ x[n]=x[n+N] $. For the signal defined as it is here, no such integer N exists.


Changing a Periodic Continuous Time Signal to a Periodic Discrete Time Signal

Suppose our sampling frequency, instead of being 1, was $ \frac{\pi}{8} $. Then the newly sampled function overlaid with the continuous function would look something like

The periodic discrete-time function $ x[n]=sin(\frac{\pi}{8}n) $ overlaid with its continuous time equivalent.
The periodic discrete-time function $ x[n]=sin(\frac{\pi}{8}n) $.


Part 2

To be completed...

Alumni Liaison

has a message for current ECE438 students.

Sean Hu, ECE PhD 2009