(fixed image alignment, added captions)
(Added explanation)
Line 38: Line 38:
 
[[Image:hw2_1_A3_ECE301Fall2008mboutin.png|thumb|left|300x300px|cos(t) shown sampled at pi/2 per unit]]
 
[[Image:hw2_1_A3_ECE301Fall2008mboutin.png|thumb|left|300x300px|cos(t) shown sampled at pi/2 per unit]]
 
[[Image:hw2_1_A4_ECE301Fall2008mboutin.png|thumb|right|300x300px|The sampling shown based on index]]
 
[[Image:hw2_1_A4_ECE301Fall2008mboutin.png|thumb|right|300x300px|The sampling shown based on index]]
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
 +
Notice that the first image of values (from the first sampling) are not periodic.  There is no integer 'N' such that sampling(n) = sampling(n+N).
 +
However, in the second case, this does occur.  One may observe that sampling(n) = sampling(n+10).  Thus, the second case is periodic.

Revision as of 10:05, 9 September 2008

The function I chose (at random) from homework1 can be found here.

The function x(t) = cos(t) is periodic in CT, as its period is 2$ \pi $. However, it is not periodic in DT.

Here is the function sampled at a frequency of 5 samples/unit:


cos(t) sampled at 5 per unit
The sampling shown based on index













Here is the function sampled at $ {\pi \over 2} $ (as closely as MATLAB is able to approximate pi)


cos(t) shown sampled at pi/2 per unit
The sampling shown based on index












Notice that the first image of values (from the first sampling) are not periodic. There is no integer 'N' such that sampling(n) = sampling(n+N). However, in the second case, this does occur. One may observe that sampling(n) = sampling(n+10). Thus, the second case is periodic.

Alumni Liaison

Questions/answers with a recent ECE grad

Ryne Rayburn