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<math>X(s)|_{s=j\omega} = X(j\omega) = \int_{-\infty}^{\infty} x(t)e^{-j\omega t} dt = F(x(t)) = X (\omega)\!</math> | <math>X(s)|_{s=j\omega} = X(j\omega) = \int_{-\infty}^{\infty} x(t)e^{-j\omega t} dt = F(x(t)) = X (\omega)\!</math> | ||
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| + | So, the Laplace Transform, <math>X(s)\!</math>, evaluated on the imaginary axis, <math>X(j\omega)\!</math>, is equal to the Fourier Transform, <math>F(x(t))\!</math>, at <math>\omega\!</math>. | ||
Revision as of 16:17, 24 November 2008
The Laplace Transform
The Laplace Transform is a generalization of the Fourier Transform. Instead of considering only the imaginary axis, $ j\omega\! $, (as the Fourier Transform does) the Laplace Transform considers all complex values represented by the general complex variable $ s\! $. Take the following simple picture:
Fourier Transform: $ x(t) --> X(\omega)\! $ where $ \omega\! $ is a frequency.
Laplace Transform: $ x(t) --> X(s)\! $ where $ s\! $ is a complex variable.
Mathematically, the Laplace Transform is represented as follows:
Let's consider the case where $ s = j\omega\! $.
$ X(s)|_{s=j\omega} = X(j\omega) = \int_{-\infty}^{\infty} x(t)e^{-j\omega t} dt = F(x(t)) = X (\omega)\! $
So, the Laplace Transform, $ X(s)\! $, evaluated on the imaginary axis, $ X(j\omega)\! $, is equal to the Fourier Transform, $ F(x(t))\! $, at $ \omega\! $.
