(New page: == Signal Energy and Power Calculations == == Background == The energy of a signal within specific time limits is defined as: <math>E=\int_{t_1}^{t_2} |x(t)|^2\, dt</math> The average...)
 
 
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<math>P=\frac{1}{t_2-t_1}\int_{t_1}^{t_2} |x(t)|^2\, dt</math>
 
<math>P=\frac{1}{t_2-t_1}\int_{t_1}^{t_2} |x(t)|^2\, dt</math>
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=== Example ===
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Given that a signal <math>\,\! x(t)=4t^2+2</math>, find the Energy and Power from <math>\,\!t_1=0</math> to <math>\,\!t_2=3</math>
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<math>\,\! E=\int_{0}^{3} |4t+2|^2\, dt
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=\int_{0}^{3} |16t^4+16t^2+4|\, dt
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=\frac{16}{5}t^5+\frac{16}{3}t^3+4t\bigg]_0^3
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=933.6</math>
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<math>\,\!
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P=\frac{1}{t_2-t_1}933.6=311.2
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</math>

Latest revision as of 15:50, 4 September 2008

Signal Energy and Power Calculations

Background

The energy of a signal within specific time limits is defined as:

$ E=\int_{t_1}^{t_2} |x(t)|^2\, dt $

The average power of a signal between specific time limits is defined as:

$ P=\frac{1}{t_2-t_1}\int_{t_1}^{t_2} |x(t)|^2\, dt $


Example

Given that a signal $ \,\! x(t)=4t^2+2 $, find the Energy and Power from $ \,\!t_1=0 $ to $ \,\!t_2=3 $

$ \,\! E=\int_{0}^{3} |4t+2|^2\, dt =\int_{0}^{3} |16t^4+16t^2+4|\, dt =\frac{16}{5}t^5+\frac{16}{3}t^3+4t\bigg]_0^3 =933.6 $

$ \,\! P=\frac{1}{t_2-t_1}933.6=311.2 $

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