Revision as of 08:06, 4 September 2008 by Serdbrue (Talk)

Given the Signal $ x(t)=3sin(2*pi*3t) $, Find the energy and power of the signal from 0 to 5 seconds.

Power

$ \int_1^5 |x(t)|^2 dt $

$ \int_1^5 |3sin(6\pi t)|^2 dt $


$ 9*\int_1^5 sin(6\pi t)^2 dt $


$ 9*\int_1^5 sin(6\pi t)^2 dt $

$ 9*(6\pi *t/2-sin(2*(6\pi *t)/4) $evaluated at 5 and 1

$ 9*(3\pi *t-sin(12\pi *t)/4) $evaluated at 5 and 1

$ 27\pi *t-9/4*sin(12\pi *t) $evaluated at 5 and 1

$ 27\pi *5-9/4*sin(12\pi *5)-(27\pi *1-9/4*sin(12\pi *1) $

$ \int_1^5 |3sin(6\pi t)|^2 dt=108\pi $

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