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Given the Signal <math>x(t)=3sin(2*pi*3t)</math>, Find the energy and power of the signal from 0 to 5 seconds. | Given the Signal <math>x(t)=3sin(2*pi*3t)</math>, Find the energy and power of the signal from 0 to 5 seconds. | ||
== Power == | == Power == | ||
| − | <math> | + | <math>\int_1^5 |x(t)|^2 dt</math> |
| − | \int_1^5 |x(t)|^2 dt< | + | |
| − | \int_1^5 |3sin( | + | <math>\int_1^5 |3sin(6\pi t)|^2 dt</math> |
| + | |||
| + | |||
| + | <math>9*\int_1^5 sin(6\pi t)^2 dt</math> | ||
Revision as of 07:51, 4 September 2008
Given the Signal $ x(t)=3sin(2*pi*3t) $, Find the energy and power of the signal from 0 to 5 seconds.
Power
$ \int_1^5 |x(t)|^2 dt $
$ \int_1^5 |3sin(6\pi t)|^2 dt $
$ 9*\int_1^5 sin(6\pi t)^2 dt $
