(Power)
(Power)
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== Power ==
 
== Power ==
 
<math>
 
<math>
\int_1^5 |x(t)|^2 dt
+
\int_1^5 |x(t)|^2 dt<\math>
 +
\int_1^5 |3sin(2\pi3t)|^2

Revision as of 07:47, 4 September 2008

Given the Signal $ x(t)=3sin(2*pi*3t) $, Find the energy and power of the signal from 0 to 5 seconds.

Power

$ \int_1^5 |x(t)|^2 dt<\math> \int_1^5 |3sin(2\pi3t)|^2 $

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