(New page: Given the Signal <math>x(t)=3sin(2*pi*3t)</math>, Find the energy and power of the signal from 0 to 5 seconds. == Power == <math> == Energy == <math>\int_1^5 |x(t)|^2) |
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Given the Signal <math>x(t)=3sin(2*pi*3t)</math>, Find the energy and power of the signal from 0 to 5 seconds. | Given the Signal <math>x(t)=3sin(2*pi*3t)</math>, Find the energy and power of the signal from 0 to 5 seconds. | ||
== Power == | == Power == | ||
| − | <math> | + | <math>\1/(5-1)int_1^5 |
== Energy == | == Energy == | ||
<math>\int_1^5 |x(t)|^2 | <math>\int_1^5 |x(t)|^2 | ||
Revision as of 07:34, 4 September 2008
Given the Signal $ x(t)=3sin(2*pi*3t) $, Find the energy and power of the signal from 0 to 5 seconds.
Power
$ \1/(5-1)int_1^5 == Energy == <math>\int_1^5 |x(t)|^2 $
