Revision as of 15:49, 4 September 2008 by Han45 (Talk)

I assumed $ x(t)=\cos(4t) $ and time interval 0 to $ 5\pi $

Energy

$ x(t) = \cos(4t) $

$ E=\int_{t1}^{t2} |x(t)|^2\, dt $

$ E=\int_{0}^{5\pi} |\cos(4t)|^2\, dt $

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Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva