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| − | == Energy | + | '''''I chose to compute the energy and power for the signal f(t) = 3x.''''' |
| + | ==Energy== | ||
| − | <math> E = \int_{T2}^{T1} | | + | <math> E = \int_{T2}^{T1} |f(t)|^2\ dt \!</math> |
| − | <br><math> E = \int_{1}^{2} | | + | <br><br><br><math> E = \int_{1}^{2} |3x|^2\ dt \!</math> |
| + | <br><br><br><math> E = \int_{1}^{2} 9x^2\ dt \!</math> | ||
| + | <br><br><math> E = [3x^3]_{t=1}^{t=2} = 21</math> | ||
| + | |||
| + | ==Power== | ||
| + | |||
| + | <br><br><br><math>P =\frac{1}{t2-t1} \int_{t1}^{t2} |f(t)|^2\ dt \!</math> | ||
| + | |||
| + | <br><br><br><math>P =\frac{1}{2-1} \int_{1}^{2} |3x|^2\ dt \!</math> | ||
| + | |||
| + | <br><br><br><math>P =\frac{1}{2-1} \int_{1}^{2} 9x^2\ dt \!</math> | ||
| + | |||
| + | <br><br><math> P = [3x^3]_{t=1}^{t=2} = 21</math> | ||
Latest revision as of 05:11, 5 September 2008
I chose to compute the energy and power for the signal f(t) = 3x.
Energy
$ E = \int_{T2}^{T1} |f(t)|^2\ dt \! $
$ E = \int_{1}^{2} |3x|^2\ dt \! $
$ E = \int_{1}^{2} 9x^2\ dt \! $
$ E = [3x^3]_{t=1}^{t=2} = 21 $
Power
$ P =\frac{1}{t2-t1} \int_{t1}^{t2} |f(t)|^2\ dt \! $
$ P =\frac{1}{2-1} \int_{1}^{2} |3x|^2\ dt \! $
$ P =\frac{1}{2-1} \int_{1}^{2} 9x^2\ dt \! $
$ P = [3x^3]_{t=1}^{t=2} = 21 $
