(Power)
(Power)
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<br><br><math> E = [x]_{t=1}^{t=2} = 1 </math>
 
<br><br><math> E = [x]_{t=1}^{t=2} = 1 </math>
<math>P_{avg}=\frac{1}{t2-t1} \int_{t1}^{t2} |f(t)|^2\ dt \!</math>
+
<br><br><br><math>P =\frac{1}{t2-t1} \int_{t1}^{t2} |f(t)|^2\ dt \!</math>

Revision as of 20:51, 4 September 2008

Energy

$ E = \int_{T2}^{T1} |x(t)|^2\ dt \! $


$ E = \int_{1}^{2} |3x|^2\ dt \! $



$ E = [x]_{t=1}^{t=2} = 1 $

Power

$ E = \int_{T2}^{T1} |x(t)|^2\ dt \! $


$ E = \int_{1}^{2} |3x|^2\ dt \! $



$ E = [x]_{t=1}^{t=2} = 1 $


$ P =\frac{1}{t2-t1} \int_{t1}^{t2} |f(t)|^2\ dt \! $

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett