Revision as of 10:50, 5 September 2008 by Nablock (Talk)

Energy

Energy of cos(2t) from t= 0 to $ 2\pi $

$ E = \int_{t1}^{t2}{|(f(t)|^2}dt $

$ E = \int_{0}^{2\pi}{|cost(2t)|^2}dt $

$ E = \frac{1}{2} \int_{0}^{2\pi}{|cost(4t)|^2}dt $

$ E = \frac{1}{2} (t + \frac{1}{4}(sin(4t))| t= 0 to 2\pi $

$ E = \frac{1}{2} (2\pi + 0) $

$ E = \pi $

Power

Power of cos(2t)

$ P = \frac{1}{t2-t1}\int_{t2}^{t1}{|f(t)|^2}dt $

Alumni Liaison

Questions/answers with a recent ECE grad

Ryne Rayburn