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Consider the signal <math>x(t)=cos(5t)</math>.
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Suppose the signal to be <math>x(t)=cos(5t)</math>.
  
 
==Energy==
 
==Energy==

Latest revision as of 13:42, 5 September 2008

Suppose the signal to be $ x(t)=cos(5t) $.

Energy

First we find the energy for one complete cycle $ E=\int_0^{2\pi}{|cos(5t)|^2dt} $


$ =\frac{1}{2}\int_0^{2\pi}(1+cos(10t))dt $


$ =\frac{1}{2}(t+\frac{1}{10}sin(10t))|_{t=0}^{t=2\pi} $


$ =\frac{1}{2}(2\pi+0-0-0) $


$ =\pi $

Energy

now we find the energy of the wave for one complete cycle

$ E=\frac{1}{2\pi-0}\int_0^{2\pi}{|cos(5t)|^2dt} $


$ =\frac{1}{2\pi-0}\frac{1}{2}\int_0^{2\pi}(1+cos(10t))dt $


$ =\frac{1}{4\pi}(t+\frac{1}{10}sin(10t))|_{t=0}^{t=2\pi} $


$ =\frac{1}{4\pi}(2\pi+0-0-0) $


$ =\frac{1}{2} $

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Recent Math PhD now doing a post-doctorate at UC Riverside.

Kuei-Nuan Lin