(Equation)
(Sources)
 
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== Equation ==
 
== Equation ==
  
<math>x(t) = cos(t) + j sin(t)</math>
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<font size="3"><math>x(t) = cos(2 \pi t)</math> from <math>0</math> to <math>5 \pi</math></font>
  
 
== Energy ==
 
== Energy ==
  
<math>E = </math>
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<math>E = \int_{0}^{5 \pi}{|cos(2 \pi t)|^2dt}</math>
 +
 
 +
<math>= \int_{0}^{5 \pi}{[1 + cos(4 \pi t)]dt}</math>
 +
 
 +
<math>=\frac{5 \pi}{2} + \frac{1}{8 \pi} sin(20 \pi^2)</math>
  
 
== Power ==
 
== Power ==
 +
 +
<math>P = \frac{1}{5 \pi - 0} \int_{0}^{5 \pi}{|cos(2 \pi t)|^2dt}</math>
 +
 +
<math>= \frac{1}{5 \pi} \int_{0}^{5 \pi}{[1 + cos(4 \pi t)]dt}</math>
 +
 +
<math>=\frac{1}{2} + \frac{1}{40 \pi^2} sin(20 \pi^2)</math>
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 +
== Sources ==
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 +
<font size="3">Lecture Notes</font>

Latest revision as of 13:47, 4 September 2008

Equation

$ x(t) = cos(2 \pi t) $ from $ 0 $ to $ 5 \pi $

Energy

$ E = \int_{0}^{5 \pi}{|cos(2 \pi t)|^2dt} $

$ = \int_{0}^{5 \pi}{[1 + cos(4 \pi t)]dt} $

$ =\frac{5 \pi}{2} + \frac{1}{8 \pi} sin(20 \pi^2) $

Power

$ P = \frac{1}{5 \pi - 0} \int_{0}^{5 \pi}{|cos(2 \pi t)|^2dt} $

$ = \frac{1}{5 \pi} \int_{0}^{5 \pi}{[1 + cos(4 \pi t)]dt} $

$ =\frac{1}{2} + \frac{1}{40 \pi^2} sin(20 \pi^2) $

Sources

Lecture Notes

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood