(cos(t-2))
(Energy)
Line 5: Line 5:
 
== Energy ==
 
== Energy ==
  
<math>u = (t-2)</math>
 
  
 
<math>E=\int_{-2}^{2\pi-2}{|cos(u)|^2du}</math>
 
<math>E=\int_{-2}^{2\pi-2}{|cos(u)|^2du}</math>

Revision as of 05:52, 5 September 2008

cos(t-2)

A time shift should not effect the energy or power of periodic function over one period. u=(t-2)

Energy

$ E=\int_{-2}^{2\pi-2}{|cos(u)|^2du} $


$ E=\frac{1}{2}\int_{-2}^{2\pi-2}(1+cos(2(u)))du $


$ E=\frac{1}{2}((u+\frac{1}{2}sin(2(u)))|_{u=-2}^{u=2\pi-2} $


$ E=\frac{1}{2}(2\pi-2 + .378 -(-2 - .378)) $


$ E=\pi $

Power

$ E=\frac{1}{2\pi-0}\int_{-2}^{2\pi-2}{|cos(u)|^2du} $


$ =\frac{1}{2\pi-0} *{\frac{1}{2}}\int_{-2}^{2\pi-2}(1+cos(2u))du $


$ =\frac{1}{4\pi}((u)+\frac{1}{2}sin(2u))|_{u=-2}^{u=2\pi-2} $


$ =\frac{1}{4\pi}(2\pi-2+.378-(-2+.378)) $


$ =\frac{1}{2} $

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva