Energy of a Signal
- $ y = 3e^{t} $ from (0,5)
- $ Energy = \int_{t1}^{t2} x(t) $
- $ Energy = \int_{0}^{5}3e^{t}dt $
- $ Energy = 3e^{5} - 3 $
Power of a Signal
- $ y = 3e^{t} $ from (0,5)
- $ Average Power = \frac{1}{t2 - t1}\int_{t1}^{t2}x(t)^2 $
- $ Average Power = \frac{1}{5}\int_{0}^{5}3e^{2t}dt $
- $ Average Power = \frac{1}{5}(\frac{1}{2}3e^{10} - 3) $
