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− | :<math>Average Power = \frac{1}{5}\int_{0}^{5}3e^{ | + | :<math>Average Power = \frac{1}{5}\int_{0}^{5}3e^{2t}dt </math> |
− | :<math>Average Power = \frac{1}{5}(3e^{ | + | :<math>Average Power = \frac{1}{5}(\frac{1}{2}3e^{10} - 3) </math> |
Revision as of 15:07, 4 September 2008
Energy of a Signal
- $ y = 3e^{t} $ from (0,5)
- $ Energy = \int_{t1}^{t2} x(t) $
- $ Energy = \int_{0}^{5}3e^{t}dt $
- $ Energy = 3e^{5} - 3 $
Power of a Signal
- $ y = 3e^{t} $ from (0,5)
- $ Average Power = \frac{1}{t2 - t1}\int_{t1}^{t2}x(t)^2 $
- $ Average Power = \frac{1}{5}\int_{0}^{5}3e^{2t}dt $
- $ Average Power = \frac{1}{5}(\frac{1}{2}3e^{10} - 3) $