(Energy of y = cos(t))
(Power of a Signal)
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== Power of a Signal ==
 
== Power of a Signal ==
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:<math> y = 3e^{t} </math> from (0,5)
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:<math>Average Power = \frac{1}{t2 - t1}\int_{t1}^{t2}x(t)^2 </math>

Revision as of 15:04, 4 September 2008

Energy of a Signal

$ y = 3e^{t} $ from (0,5)
$ Energy = \int_{t1}^{t2} x(t) $
$ Energy = \int_{0}^{5}3e^{t}dt $
$ Energy = 3e^{5} - 3 $


Power of a Signal

$ y = 3e^{t} $ from (0,5)
$ Average Power = \frac{1}{t2 - t1}\int_{t1}^{t2}x(t)^2 $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood