(New page: == Energy of y = cos(t) == y = cos(t) t1 = 0 t2 = pi) |
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| − | == Energy of | + | == Energy of a Signal== |
| − | + | :<math> y = 3e^{t} </math> from (0,5) | |
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| − | + | :<math> Energy = \int_{t1}^{t2} x(t) </math> | |
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| + | :<math> Energy = \int_{0}^{5}3e^{t}dt </math> | ||
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| + | :<math> Energy = 3e^{5} - 3 </math> | ||
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| + | == Power of a Signal == | ||
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| + | :<math> y = 3e^{t} </math> from (0,5) | ||
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| + | :<math>Average Power = \frac{1}{t2 - t1}\int_{t1}^{t2}x(t)^2 </math> | ||
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| + | :<math>Average Power = \frac{1}{5}\int_{0}^{5}3e^{2t}dt </math> | ||
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| + | :<math>Average Power = \frac{1}{5}(\frac{3}{2}e^{10} - \frac{3}{2}) </math> | ||
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| + | :<math>Average Power = \frac{3}{10}e^{10} - \frac{3}{10} </math> | ||
Latest revision as of 15:09, 4 September 2008
Energy of a Signal
- $ y = 3e^{t} $ from (0,5)
- $ Energy = \int_{t1}^{t2} x(t) $
- $ Energy = \int_{0}^{5}3e^{t}dt $
- $ Energy = 3e^{5} - 3 $
Power of a Signal
- $ y = 3e^{t} $ from (0,5)
- $ Average Power = \frac{1}{t2 - t1}\int_{t1}^{t2}x(t)^2 $
- $ Average Power = \frac{1}{5}\int_{0}^{5}3e^{2t}dt $
- $ Average Power = \frac{1}{5}(\frac{3}{2}e^{10} - \frac{3}{2}) $
- $ Average Power = \frac{3}{10}e^{10} - \frac{3}{10} $
