Revision as of 09:46, 5 September 2008 by Jmazzei (Talk)

For a Continuous Time Signal

Energy from $ t_{1} $ to $ t_{2} $

$ E = \int_{t_1}^{t_2}\!|x(t)|^2\ dt $

Average power in time interval from [$ t_{1},t_{2} $]:

$ P_{avg} = \frac{1}{{t_2}-{t_1}}\int_{t_1}^{t_2}\!|x(t)|^2\ dt $

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Ryne Rayburn