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=\frac{4}{5}t^5+\frac{4}{3}t^3+t\bigg]_0^3 | =\frac{4}{5}t^5+\frac{4}{3}t^3+t\bigg]_0^3 | ||
| − | =905.4</math> | + | =905.4</math>Joules. |
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<math>\,\! | <math>\,\! | ||
| − | P=\frac{1}{t_2-t_1}905.4=301. | + | P=\frac{1}{t_2-t_1}905.4=301.8watts. |
</math> | </math> | ||
Revision as of 13:20, 5 September 2008
Jayanth Athreya H.w 1.5 Computation of Signal Energy and power. Source for definition Of Continuous Signal: Wikipedia.
Continuous signal:A continuous signal or a continuous-time signal is a varying quantity (a signal) that is expressed as a function of a real-valued domain, usually time. The function of time need not be continuous.
Example
Given that a signal
$ \,\! x(t)=2t^2+1 $, find the Energy and Power from $ \,\!t_1=1 $ to $ \,\!t_2=4 $
$ \,\! E=\int_{1}^{4} |2t^2+1|^2\, dt =\int_{1}^{4} |4t^4+4t^2+1|\, dt =\frac{4}{5}t^5+\frac{4}{3}t^3+t\bigg]_0^3 =905.4 $Joules.
$ \,\! P=\frac{1}{t_2-t_1}905.4=301.8watts. $
