Revision as of 10:28, 5 September 2008 by Zhang79 (Talk)

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Signal Power

The average power over an interval of time $ [t_1,t_2]\! $ is $ P_{avg}=\frac{1}{t_2-t_1}\int_{t_1}^{t_2} |x(t)|^2\ dt \! $.

Given that $ y(t) = cos(2*pi*t) \! $ and time interval $ [0,2]\! $, 1/(2-0)


Signal Energy

The equation to calculate signal energy is as follows: $ E=\int_{t_1}^{t_2}x(t)dt $

using the same equation $ y(t) = cos(2*pi*t) \! $ over a time interval $ [0,2]\! $ as the previous section,

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood