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==Energy== | ==Energy== | ||
| − | <math>E=\int_3^{5}{\dfrac{2t}{t^2+5} | + | <math>E=\int_3^{5}{\dfrac{2t}{t^2+5}dt}</math> |
Revision as of 14:21, 4 September 2008
Compute the Energy and Power of the signal $ x(t)=\dfrac{2t}{t^2+5} $ between 3 and 5 seconds.
Energy
$ E=\int_3^{5}{\dfrac{2t}{t^2+5}dt} $
