(Signal Energy)
(Signal Energy)
Line 6: Line 6:
  
 
<math>E=\int_{0}^{1}|e^(4t)|^2dt</math>
 
<math>E=\int_{0}^{1}|e^(4t)|^2dt</math>
 +
 +
<math>E=\int_{0}^{1}|e^(8t)dt</math>
 +
 +
<math> = \frac{1}{8}[e^{8t}]_{t=0}^{t=1} \!</math>
 +
<math> = \frac{1}{8}(e^8 -1)\!</math>

Revision as of 08:47, 5 September 2008

Signal Energy

$ E=\int_{t_1}^{t_2}x(t)dt $

find the signal energy of $ x(t)=e^{4t}\! $ on $ [0,1]\! $

$ E=\int_{0}^{1}|e^(4t)|^2dt $

$ E=\int_{0}^{1}|e^(8t)dt $

$ = \frac{1}{8}[e^{8t}]_{t=0}^{t=1} \! $ $ = \frac{1}{8}(e^8 -1)\! $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood