(Calculating the Energy of a Function)
(Calculating the Power of a Function)
 
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<math>=\int_0^{2\pi}(1-cos(2t))dt</math>
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<math>E=\int_0^{2\pi}(1-cos(2t))dt</math>
  
  
<math>=(t-\frac{1}{2}sin(2t))|_{t=0}^{t=2\pi}</math>
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<math>E=(t-\frac{1}{2}sin(2t))|_{t=0}^{t=2\pi}</math>
  
  
<math>=2\pi)</math>
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<math>E= 2{\pi}</math>
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== Calculating the Power of a Function ==
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After you have the energy of a function, calculating the power isn't very difficult. Use the following equation.
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<math>E=\frac{1}{t_2 - t_1}\int_{t1}^{t2}{|f(x)|^2}</math>
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For our previous example, continue by following below.
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<math>E=\frac{1}{2{\pi} - 0}\int_{t1}^{t2}{|f(x)|^2}</math>
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<math>E=\frac{1}{2{\pi} - 0}*{2\pi}</math>
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<math>E= 1

Latest revision as of 16:07, 5 September 2008

Calculating the Energy of a Function

To calculate the energy of a function, use the following equation.

$ E=\int_{t1}^{t2}{|f(t)|^2dt} $

For clarity, follow the example below.

$ E=\int_{0}^{2\pi}{|2sin(t)|^2dt} $


$ E=2\int_{0}^{2\pi}{|sin(t)|^2dt} $


$ E=\int_0^{2\pi}(1-cos(2t))dt $


$ E=(t-\frac{1}{2}sin(2t))|_{t=0}^{t=2\pi} $


$ E= 2{\pi} $

Calculating the Power of a Function

After you have the energy of a function, calculating the power isn't very difficult. Use the following equation.

$ E=\frac{1}{t_2 - t_1}\int_{t1}^{t2}{|f(x)|^2} $

For our previous example, continue by following below.

$ E=\frac{1}{2{\pi} - 0}\int_{t1}^{t2}{|f(x)|^2} $

$ E=\frac{1}{2{\pi} - 0}*{2\pi} $

$ E= 1 $

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