Revision as of 19:26, 2 September 2008 by Park1 (Talk)

Consider the signal $ x(t)=cos(t) $.

Energy

We will find the energy in one cycle of the cosine waveform.

$ E=\int_0^{2\pi}{|cos(t)|^2dt} $


$ =\frac{1}{2}\int_0^{2\pi}(1+cos(2t))dt $


$ =\frac{1}{2}(t+\frac{1}{2}sin(2t))|_{t=0}^{t=2\pi} $


$ =\frac{1}{2}(2\pi+0-0-0) $


$ =\pi $

Energy

We will find the average power in one cycle of the cosine waveform.

$ E=\frac{1}{2\pi-0}\int_0^{2\pi}{|cos(t)|^2dt} $


$ =\frac{1}{2\pi-0}\frac{1}{2}\int_0^{2\pi}(1+cos(2t))dt $


$ =\frac{1}{4\pi}(t+\frac{1}{2}sin(2t))|_{t=0}^{t=2\pi} $


$ =\frac{1}{4\pi}(2\pi+0-0-0) $


$ =\frac{1}{2} $

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang