(New page: Consider the signal <math>x(t)=cos(t)</math>. ==Energy== We will find the energy in one cycle of the cosine waveform. <math>E=\int_0^{2\pi}{|cos(t)|^2dt}</math> <math>=\frac{1}{2}\int_...) |
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Revision as of 19:26, 2 September 2008
Consider the signal $ x(t)=cos(t) $.
Energy
We will find the energy in one cycle of the cosine waveform.
$ E=\int_0^{2\pi}{|cos(t)|^2dt} $
$ =\frac{1}{2}\int_0^{2\pi}(1+cos(2t))dt $
$ =\frac{1}{2}(t+\frac{1}{2}sin(2t))|_{t=0}^{t=2\pi} $
$ =\frac{1}{2}(2\pi+0-0-0) $
$ =\pi $
Energy
We will find the average power in one cycle of the cosine waveform.
$ E=\frac{1}{2\pi-0}\int_0^{2\pi}{|cos(t)|^2dt} $
$ =\frac{1}{2\pi-0}\frac{1}{2}\int_0^{2\pi}(1+cos(2t))dt $
$ =\frac{1}{4\pi}(t+\frac{1}{2}sin(2t))|_{t=0}^{t=2\pi} $
$ =\frac{1}{4\pi}(2\pi+0-0-0) $
$ =\frac{1}{2} $
