(→Average Power of a Signal) |
(→Energy of a signal) |
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<math>Energy = \int_{0}^{2 \pi}\!(\frac{1-cos(2t)}{2}) dt</math> | <math>Energy = \int_{0}^{2 \pi}\!(\frac{1-cos(2t)}{2}) dt</math> | ||
| − | <math>Energy = \ | + | <math>Energy = \pi - \frac{1}{4} \sin(4 \pi)</math> |
| + | |||
| + | <math>\ Energy = \pi </math> | ||
==Average Power of a Signal== | ==Average Power of a Signal== | ||
<math>Avgerage Power = {1\over(t_2-t_1)}\int_{t_1}^{t_2}\!|x(t)|^2 dt</math> | <math>Avgerage Power = {1\over(t_2-t_1)}\int_{t_1}^{t_2}\!|x(t)|^2 dt</math> | ||
Revision as of 15:44, 5 September 2008
Energy of a signal
Consider the signal $ \ y = \sin(t) $ Lets find the energy over one cycle:
$ Energy = \int_{t_1}^{t_2}\!|x(t)|^2 dt $
$ Energy = \int_{0}^{2 \pi}\!|sin(t)|^2 dt $
$ Energy = \int_{0}^{2 \pi}\!(\frac{1-cos(2t)}{2}) dt $
$ Energy = \pi - \frac{1}{4} \sin(4 \pi) $
$ \ Energy = \pi $
Average Power of a Signal
$ Avgerage Power = {1\over(t_2-t_1)}\int_{t_1}^{t_2}\!|x(t)|^2 dt $
