(Non-periodic Functions)
(Periodic Functions)
 
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A Discrete Time signal is said to be periodic if there exists <math>\ N > 0</math> (where N is an integer) such that <math>\ x[n+N]=x[n]</math>
 
A Discrete Time signal is said to be periodic if there exists <math>\ N > 0</math> (where N is an integer) such that <math>\ x[n+N]=x[n]</math>
  
An example of a CT periodic signal is <math>x(t) = sawtooth(t)</math>:
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An example of a CT periodic signal is <math>x(t) = sawtooth(t,.5)</math> (which is actually a tri wave):
  
[[Image:saw_ECE301Fall2008mboutin.jpg]]
+
[[Image:tri_ECE301Fall2008mboutin.jpg]]
  
 
As you can see the function has a fundamental period of two Pi. Therefore any multiple of two Pi is a period.
 
As you can see the function has a fundamental period of two Pi. Therefore any multiple of two Pi is a period.

Latest revision as of 12:21, 5 September 2008

Periodic Functions

A Continuous Time signal is said to be periodic if there exists $ \ T > 0 $ such that $ \ x(t+T)=x(t) $

A Discrete Time signal is said to be periodic if there exists $ \ N > 0 $ (where N is an integer) such that $ \ x[n+N]=x[n] $

An example of a CT periodic signal is $ x(t) = sawtooth(t,.5) $ (which is actually a tri wave):

Tri ECE301Fall2008mboutin.jpg

As you can see the function has a fundamental period of two Pi. Therefore any multiple of two Pi is a period.

Non-periodic Functions

A Continuous Time signal is said to be non-periodic if there is no value of $ \ T > 0 $ that satisfies $ \ x(t+T)=x(t) $

A Discrete Time signal is said to be non-periodic if there is no value of $ \ N > 0 $ (where N is an integer) that satisfies$ \ x[n+N]=x[n] $

An example of a non-periodic continuous time signal would be $ \ x(t) = e^{(-1 + j)t} $. This goes to show that not all complex exponential functions are periodic.

Here is what the function looks like when graphed:

Np exp ECE301Fall2008mboutin.jpg

As you can see from the graph the function is non-periodic.

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