(a)
 
(a)
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z2=c+id
 
z2=c+id
  
<math>\,\frac{(a + bi)}{(c + di)} = \frac{(ac + bd)}{(c^2 + d^2)} + \frac{(bc - ad)}{(c^2 + d^2)}i\,</math>
+
<math>\,\frac{z1}{z2}=\frac{(a + bi)}{(c + di)} = \frac{(ac + bd)}{(c^2 + d^2)} + \frac{(bc - ad)}{(c^2 + d^2)}i\,</math>

Revision as of 20:18, 4 September 2008

Defination

Complex numbers be defined as numbers having a real part which is followed by an imaginary part. The imaginary part is either denoted by 'i' or they are denoted by 'j'. thecomplex number is simply denoted by $ i=\sqrt{-1} $. They are generally written as a+ib and are represented on a complex plane in both Cartesian(x,y) and polar form(r,theta). The Cartesian and the polar form are inter-convertible where $ r=\sqrt{x^2+y^2} $ and $ theta=\tan^{-1}{y/x} $.

general

$ i=\sqrt{-1} $

$ i^2=\ {-1} $

$ i^3=\ {-i} $

$ i=\ { 1} $

addition

z1=a+ib

z2=c+id

$ z1+z2=\ (a+c)+i(b+d) $

subtraction

z1=a+ib

z2=c+id

$ z1-z2=\ (a-c)+i(b-d) $

multiplication

z1=a+ib

z2=c+id

$ z1*z2=\ (ac-bd)+i(bc+ad) $

division

z1=a+ib

z2=c+id

$ \,\frac{z1}{z2}=\frac{(a + bi)}{(c + di)} = \frac{(ac + bd)}{(c^2 + d^2)} + \frac{(bc - ad)}{(c^2 + d^2)}i\, $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood