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<math>=\left(\frac{\left(1+i\right)^2}{\left(1-i\right)\times\left(1+i\right)}\right)^4</math> | <math>=\left(\frac{\left(1+i\right)^2}{\left(1-i\right)\times\left(1+i\right)}\right)^4</math> | ||
| − | <math>=( | + | <math>=\left(\frac{1+2i+\left(i\right)^2}{1^2-\left(i\right)^2}\right)^4</math> |
<math>=((1+2i-1)/(1-(-1)))^4</math> | <math>=((1+2i-1)/(1-(-1)))^4</math> | ||
Revision as of 10:39, 4 September 2008
complex number combined sum of a real number and an imaginary number. the basic expression of complex number is a + bi.(a and b are real numbers) An imaginary number is a multiple of i, it mean i is $ \sqrt-1 $.
for example of complex number. calculate this. $ (4+3\sqrt2i)-(2-\sqrt2i) $
answer:
$ = 4+3\sqrt2i - 2+\sqrt2i $ $ = (4-2) + (3\sqrt2 + \sqrt2)i $ $ =2 + 4\sqrt2i $
another example,
change to $ a+bi $ form.
$ ((1+i)/(1-i))^4 $
answer:
$ =\left(\frac{\left(1+i\right)^2}{\left(1-i\right)\times\left(1+i\right)}\right)^4 $ $ =\left(\frac{1+2i+\left(i\right)^2}{1^2-\left(i\right)^2}\right)^4 $ $ =((1+2i-1)/(1-(-1)))^4 $ $ =(2i/2)^4 $ $ =i^4 $ $ =((i)^2)^2 $ $ =(-1)^2=1 $ $ =1 + 0i $
