(3 intermediate revisions by the same user not shown)
Line 2: Line 2:
  
 
for example of complex number.
 
for example of complex number.
 +
 
calculate this.
 
calculate this.
 +
 
<math>(4+3\sqrt2i)-(2-\sqrt2i)</math>
 
<math>(4+3\sqrt2i)-(2-\sqrt2i)</math>
  
Line 18: Line 20:
 
           <math>=\left(\frac{\left(1+i\right)^2}{\left(1-i\right)\times\left(1+i\right)}\right)^4</math>
 
           <math>=\left(\frac{\left(1+i\right)^2}{\left(1-i\right)\times\left(1+i\right)}\right)^4</math>
 
          
 
          
           <math>=((1+2i+(i)^2)/(i^2-(i)^2))^4</math>
+
           <math>=\left(\frac{1+2i+\left(i\right)^2}{1^2-\left(i\right)^2}\right)^4</math>
 
          
 
          
           <math>=((1+2i-1)/(1-(-1)))^4</math>
+
           <math>=\left(\frac{1+2i-1}{1-\left(-1\right)}\right)^4</math>
 
          
 
          
           <math>=(2i/2)^4</math>
+
           <math>=\left(\frac{2i}{2}\right)^4</math>
 
          
 
          
 
           <math>=i^4</math>
 
           <math>=i^4</math>
Line 30: Line 32:
 
           <math>=(-1)^2=1</math>
 
           <math>=(-1)^2=1</math>
 
          
 
          
           <math>=1 + 0i</math>'''
+
           <math>=1 + 0i</math>

Latest revision as of 10:46, 4 September 2008

complex number combined sum of a real number and an imaginary number. the basic expression of complex number is a + bi.(a and b are real numbers) An imaginary number is a multiple of i, it mean i is $ \sqrt-1 $.

for example of complex number.

calculate this.

$ (4+3\sqrt2i)-(2-\sqrt2i) $

answer:

       $ = 4+3\sqrt2i - 2+\sqrt2i $
       $ = (4-2) + (3\sqrt2 + \sqrt2)i $
       $ =2 + 4\sqrt2i $

another example,

change to $ a+bi $ form.

$ ((1+i)/(1-i))^4 $

answer:

         $ =\left(\frac{\left(1+i\right)^2}{\left(1-i\right)\times\left(1+i\right)}\right)^4 $
       
          $ =\left(\frac{1+2i+\left(i\right)^2}{1^2-\left(i\right)^2}\right)^4 $
       
          $ =\left(\frac{1+2i-1}{1-\left(-1\right)}\right)^4 $
       
          $ =\left(\frac{2i}{2}\right)^4 $
       
          $ =i^4 $
       
          $ =((i)^2)^2 $
       
          $ =(-1)^2=1 $
       
          $ =1 + 0i $

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang