(→Finding the Inverse of Complex Numbers) |
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== Finding the Inverse of Complex Numbers == | == Finding the Inverse of Complex Numbers == | ||
| − | <math>{(a+bi)^{-1}}={1\over(a + bi)} = {a\over a^2+b^2}+ \left( {-b\over a^2+b^2}\right)i</math> | + | Here is the property for taking the inverse of a complex number. Take <math>{1\over(a + bi)}</math> and multiply by <math>{(a - bi)\over(a - bi)}</math>. |
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| + | This will also separate the complex number into a real part and an imaginary part. | ||
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| + | <math>{(a + bi)^{-1}}={1\over(a + bi)} = {a\over a^2 + b^2}+ \left( {-b\over a^2 + b^2}\right)i</math> | ||
[http://en.wikipedia.org/wiki/Complex_number Wikipedia(Complex Numbers)] | [http://en.wikipedia.org/wiki/Complex_number Wikipedia(Complex Numbers)] | ||
Latest revision as of 03:20, 5 September 2008
Finding the Inverse of Complex Numbers
Here is the property for taking the inverse of a complex number. Take $ {1\over(a + bi)} $ and multiply by $ {(a - bi)\over(a - bi)} $.
This will also separate the complex number into a real part and an imaginary part.
$ {(a + bi)^{-1}}={1\over(a + bi)} = {a\over a^2 + b^2}+ \left( {-b\over a^2 + b^2}\right)i $
