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== Finding the Inverse of Complex Numbers == | == Finding the Inverse of Complex Numbers == | ||
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| + | <math>1/(a + bi) = {a\over a^2+b^2}+ \left( {-b\over a^2+b^2}\right)i</math> | ||
Revision as of 04:23, 2 September 2008
Finding the Inverse of Complex Numbers
$ 1/(a + bi) = {a\over a^2+b^2}+ \left( {-b\over a^2+b^2}\right)i $
