(New page: ==Why?== Complex Numbers make it possible to solve square roots of negative numbers and for engineers, they make it easier to solve complex differential equations. Usually complex numbers ...)
 
 
(3 intermediate revisions by the same user not shown)
Line 1: Line 1:
 
==Why?==
 
==Why?==
Complex Numbers make it possible to solve square roots of negative numbers and for engineers, they make it easier to solve complex differential equations. Usually complex numbers are of the form <math>a+bi</math>,where a is the real part of the number and b is the imaginary part with <math>i=\sqrt(-1)<\math>, but using i is arbitrary. it can be anything. i is convenient because imaginary begins with i, but we will mostly use j to denote <math>sqrt(-1)</math>
+
Complex Numbers make it possible to solve square roots of negative numbers and for engineers, they make it easier to solve complex differential equations. Usually complex numbers are of the form <math>a+bi</math>,where a is the real part of the number and b is the imaginary part with <math>i=\sqrt{-1}</math>, but using i is arbitrary. it can be anything. i is convenient because imaginary begins with i, but we will mostly use j to denote <math>\sqrt{-1}</math>
  
 
==Properties==
 
==Properties==
 +
 
<math>j^{4n}=j</math>
 
<math>j^{4n}=j</math>
 +
 
<math>j^{4n+1}=-1</math>
 
<math>j^{4n+1}=-1</math>
 +
 
<math>j^{4n+2}=-j</math>
 
<math>j^{4n+2}=-j</math>
 +
 
<math>j^{4n+3}=1</math>
 
<math>j^{4n+3}=1</math>
 +
 
where n is a whole number.
 
where n is a whole number.
  
Line 38: Line 43:
 
This formula is very useful when working with signals.
 
This formula is very useful when working with signals.
  
<math>e^{wjt)=cos(wt)+jsin(wt)</math>
+
<math>e^{wjt}=cos{wt}+jsin{wt}</math>

Latest revision as of 13:43, 4 September 2008

Why?

Complex Numbers make it possible to solve square roots of negative numbers and for engineers, they make it easier to solve complex differential equations. Usually complex numbers are of the form $ a+bi $,where a is the real part of the number and b is the imaginary part with $ i=\sqrt{-1} $, but using i is arbitrary. it can be anything. i is convenient because imaginary begins with i, but we will mostly use j to denote $ \sqrt{-1} $

Properties

$ j^{4n}=j $

$ j^{4n+1}=-1 $

$ j^{4n+2}=-j $

$ j^{4n+3}=1 $

where n is a whole number.

Ex:

$ j^9=j^{4*2+1}=j^8*j^1=1*j=j+ $

Addition

$ (a+bj)+(c+dj)=(a+c)+(b+d)j $

Ex:

$ (7+3j)+(4+5j)=(7+4)+(3+5)j=11+8j $ $ (7+3j)-(4+5j)=(7-4)+(3-5)j=3-2j $

Multiplication

$ (a+bj)*(c+dj)=a*c+a*dj+bj*c+bj*dj=(a*c-b*d)+(a*d+b*c)j $

Ex:

$ (2+3j)*(4+5j)=2*4+2*5j+3j*4+3j*5j=(2*4-3*5)+(2*5+3*4)j=-7+22j $

Conjugate

Suppose $ n=a+bj $, then the conjugate of n, m, is defined as $ m=a-bj $. Note: When multiplying conjugate pairs, the result is no longer an imaginary number. $ (a+bj)*(a-bj)=a*a-a*bj+bj*a+b^2=a^2+b^2 $

Euler's Formula

This formula is very useful when working with signals.

$ e^{wjt}=cos{wt}+jsin{wt} $

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett