(New page: ==Why?== Complex Numbers make it possible to solve square roots of negative numbers and for engineers, they make it easier to solve complex differential equations. Usually complex numbers ...) |
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==Why?== | ==Why?== | ||
| − | Complex Numbers make it possible to solve square roots of negative numbers and for engineers, they make it easier to solve complex differential equations. Usually complex numbers are of the form <math>a+bi</math>,where a is the real part of the number and b is the imaginary part with <math>i= | + | Complex Numbers make it possible to solve square roots of negative numbers and for engineers, they make it easier to solve complex differential equations. Usually complex numbers are of the form <math>a+bi</math>,where a is the real part of the number and b is the imaginary part with <math>i=sqrt(-1)<\math>, but using i is arbitrary. it can be anything. i is convenient because imaginary begins with i, but we will mostly use j to denote <math>sqrt(-1)</math> |
==Properties== | ==Properties== | ||
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This formula is very useful when working with signals. | This formula is very useful when working with signals. | ||
| − | <math> | + | <math>exp^{wjt)=cos(wt)+jsin(wt)</math> |
Revision as of 13:30, 4 September 2008
Why?
Complex Numbers make it possible to solve square roots of negative numbers and for engineers, they make it easier to solve complex differential equations. Usually complex numbers are of the form $ a+bi $,where a is the real part of the number and b is the imaginary part with $ i=sqrt(-1)<\math>, but using i is arbitrary. it can be anything. i is convenient because imaginary begins with i, but we will mostly use j to denote <math>sqrt(-1) $
Properties
$ j^{4n}=j $ $ j^{4n+1}=-1 $ $ j^{4n+2}=-j $ $ j^{4n+3}=1 $ where n is a whole number.
Ex:
$ j^9=j^{4*2+1}=j^8*j^1=1*j=j+ $
Addition
$ (a+bj)+(c+dj)=(a+c)+(b+d)j $
Ex:
$ (7+3j)+(4+5j)=(7+4)+(3+5)j=11+8j $ $ (7+3j)-(4+5j)=(7-4)+(3-5)j=3-2j $
Multiplication
$ (a+bj)*(c+dj)=a*c+a*dj+bj*c+bj*dj=(a*c-b*d)+(a*d+b*c)j $
Ex:
$ (2+3j)*(4+5j)=2*4+2*5j+3j*4+3j*5j=(2*4-3*5)+(2*5+3*4)j=-7+22j $
Conjugate
Suppose $ n=a+bj $, then the conjugate of n, m, is defined as $ m=a-bj $. Note: When multiplying conjugate pairs, the result is no longer an imaginary number. $ (a+bj)*(a-bj)=a*a-a*bj+bj*a+b^2=a^2+b^2 $
Euler's Formula
This formula is very useful when working with signals.
$ exp^{wjt)=cos(wt)+jsin(wt) $
