(Proof)
(Proof)
Line 12: Line 12:
  
 
<math> \sin x = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \cdots </math>
 
<math> \sin x = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \cdots </math>
 +
 +
 +
<math> e^{ix} = 1 + ix + /frac{{ix}^2}{2!} + /frac{{ix}^3}{3!} + /frac{{ix}^4}{4!} + /frac{{ix}^5}{5!} + \cdots </math>

Revision as of 04:52, 5 September 2008

Euler's Forumla

$ e^{ix} = \cos x + i * \sin x $

Proof

Using Taylor Series:

$ e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \cdots $

$ \cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \cdots $

$ \sin x = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \cdots $


$ e^{ix} = 1 + ix + /frac{{ix}^2}{2!} + /frac{{ix}^3}{3!} + /frac{{ix}^4}{4!} + /frac{{ix}^5}{5!} + \cdots $

Alumni Liaison

BSEE 2004, current Ph.D. student researching signal and image processing.

Landis Huffman