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<math>\sum_{n = M}^N \alpha^n = \alpha^M - \alpha^{N-1}</math>
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<math>\sum_{n = M}^N \alpha^n = \alpha^M - \alpha^{N-1} / (1 - \alpha)</math>

Revision as of 02:42, 20 July 2009

$ \sum_{n = M}^N \alpha^n = \alpha^M - \alpha^{N-1} / (1 - \alpha) $

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett