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<math>\sum_{n = M}^N \alpha^n</math>
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<math>\sum_{n = M}^N \alpha^n = \alpha^M - \alpha^{N-1}</math>

Revision as of 02:41, 20 July 2009

$ \sum_{n = M}^N \alpha^n = \alpha^M - \alpha^{N-1} $

Alumni Liaison

Prof. Math. Ohio State and Associate Dean
Outstanding Alumnus Purdue Math 2008

Jeff McNeal