(New page: {| |- | align="right" style="padding-right: 1em;" | Inverse DT Fourier Transform | <math>\, x(t)=\mathcal{F}^{-1}(\mathcal{X}(\omega))=\mathcal{F}^{-1}(\mathcal{X}(2\pi f))=\frac{1}{2\pi}...) |
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| <math>\, x(t)=\mathcal{F}^{-1}(\mathcal{X}(\omega))=\mathcal{F}^{-1}(\mathcal{X}(2\pi f))=\frac{1}{2\pi}\int_{-\infty}^{\infty}\mathcal{X}(2\pi f)e^{i2\pi ft} d2\pi f= \int_{-\infty}^{\infty}X(f)e^{i2\pi ft} df \,</math> | | <math>\, x(t)=\mathcal{F}^{-1}(\mathcal{X}(\omega))=\mathcal{F}^{-1}(\mathcal{X}(2\pi f))=\frac{1}{2\pi}\int_{-\infty}^{\infty}\mathcal{X}(2\pi f)e^{i2\pi ft} d2\pi f= \int_{-\infty}^{\infty}X(f)e^{i2\pi ft} df \,</math> | ||
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Revision as of 20:48, 9 September 2010
| Inverse DT Fourier Transform |
| $ \, x(t)=\mathcal{F}^{-1}(\mathcal{X}(\omega))=\mathcal{F}^{-1}(\mathcal{X}(2\pi f))=\frac{1}{2\pi}\int_{-\infty}^{\infty}\mathcal{X}(2\pi f)e^{i2\pi ft} d2\pi f= \int_{-\infty}^{\infty}X(f)e^{i2\pi ft} df \, $ |
